WikiDiscuss

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> On Sat, Nov 06, 2004 at 09:12:22AM -0800, Jorge Llamb?as wrote:
> >
> > --- John Cowan wrote:
> >
> > > The idea is that if a text can be quoted by lu...li'u, it can
> > > also be quoted by lo'u...le'u. Therefore, embedded zoi and
> > > lo'u...le'u quotations should be processed even though
> > > everything else is not.
> >
> > Then embedded {zo} also has to be processed, not only for {zo
> > le'u} but also at least for {zo lo'u}, {zo zoi} and {zo zo}.
> >
> > Otherwise you get things like
> >
> > {lu zo zoi lo'u non-lojban le'u lo'u other non-lojban le'u li'u}
> >
> > being valid, but
> >
> > {lo'u zo zoi lo'u non-lojban le'u lo'u other non-lojban le'u le'u}
> >
> > invalid.
>
> As far as I can tell, neither of those are valid regardless. In the
> first case, "non-lojban" is in a lo'u...le'u quote but not a zoi
> quote (because zoi was quoted), so parsing fails (all words in
> lo'u..le'u must still be Lojban). In the second case, even if zo
> doesn't work on zoi, "other non-lojban" is still outside of the zoi
> quote, so it still fails.

You're right, bad example. Consider this one:

{lu zo zoi lo'u da le'u li'u}

is valid. But:

{lo'u zo zoi lo'u da le'u le'u}

is not valid if the {zoi} is active, even if {le'u} is changed
to {zo le'u}, because the zoi quote is never closed.

mu'o mi'e xorxes

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