History: Rearranging arguments without using FA

Source of version: 2 (current)

So you want to re-arrange the order of arguments of your ((selbri)) but don't want to use FA, and can't figure out which cmavo from SE to use and in which order to achieve the desired result? This page will tell you how to. Imagine that you have five selbri with different number of places: x1 broda, x1 x2 brode, x1 x2 x3 brodi, x1 x2 x3 x4 brodo, and x1 x2 x3 x4 x5 brodu. Then here's how to rearrange them in the order you want. (Note that in some cases, more than one possibility exists, even if you rule out non-shortest-length things such as sticking in ''se se'' somewhere. In such a case, I picked the alphabetically first method.) !!!How to use this table Imagine that you want to use ''cusku'' but want to put the quotation after the audience. Then instead of saying ''mi cusku fi le patfu be mi fe lu na go'i li'u'', you'd consider that you want to convert ''x1 x2 x3 x4 cusku'' into ''x1 x3 x2 x4 XXX cusku'', where ''XXX'' is the desired sequence of SE cmavo. The table is sorted so that the last sumti place starts at x1 and rises. Since ''cusku'' takes four arguments, look up the table under ''x1 x2 x3 x4 brodo'' and look for sequences ending with ''x4'' (which will be toward the end since x4 is the largest-numbered argument for four-argument selbri) and find ''x1 x3 x2 x4 se te se brodo'', and you'll know that you could also say ''mi setese cusku le patfu be mi lu na go'i li'u''. Simple! You could also ignore final places and look for ''x1 x3 x2'' and find ''se te se brodi''; as you see, the sequence of SE is the same. Goodbye FA :) You could also use this table in the other direction. For example, ((What does it mean?)) asks what ''xelseltervelterklama'' means. By using the full table (not reproduced here, but available on request from ((pne|me))), one can see that ''x5 x1 x4 x3 x2 xe se te ve te brodu'' is the same as ''x1 x2 x3 x4 x5 brodu'', or in other words, x1 of ''xe se te ve te brodu'' is x5 of ''brodu'', and so on. So ''xe se te ve te klama'' has order x5, x1, x4, x3, x2 of ''klama'', or in other words: #vehicle #go-er #route #origin #destination (The version chosen in this table for this particular reordering is ''te ve te xe se brodu''. Showing that the two are equivalent is left as an exercise to the reader.) !!!x1 broda * x1 broda !!!x1 x2 brode * x1 x2 brode * x2 x1 se brode !!!x1 x2 x3 brodi * x3 x2 x1 te brodi * x2 x3 x1 se te brodi * x3 x1 x2 te se brodi * x1 x3 x2 se te se brodi * x2 x1 x3 se brodi * x1 x2 x3 brodi !!!x1 x2 x3 x4 brodo * x4 x3 x2 x1 se te se ve brodo * x3 x4 x2 x1 te se ve brodo * x4 x2 x3 x1 ve brodo * x2 x4 x3 x1 se ve brodo * x3 x2 x4 x1 te ve brodo * x2 x3 x4 x1 se te ve brodo * x4 x3 x1 x2 ve se te brodo * x3 x4 x1 x2 se ve se te brodo * x4 x1 x3 x2 ve se brodo * x1 x4 x3 x2 se ve se brodo * x3 x1 x4 x2 te ve se brodo * x1 x3 x4 x2 se te ve se brodo * x4 x2 x1 x3 ve te brodo * x2 x4 x1 x3 se ve te brodo * x4 x1 x2 x3 ve te se brodo * x1 x4 x2 x3 se ve te se brodo * x1 x4 x2 x3 ve te se ve brodo * x2 x1 x4 x3 se te ve te brodo * x1 x2 x4 x3 te ve te brodo * x3 x2 x1 x4 te brodo * x2 x3 x1 x4 se te brodo * x3 x1 x2 x4 te se brodo * x1 x3 x2 x4 se te se brodo * x2 x1 x3 x4 se brodo * x1 x2 x3 x4 brodo !!!x1 x2 x3 x4 x5 brodu * x5 x4 x3 x2 x1 se ve se xe brodu * x4 x5 x3 x2 x1 ve se xe brodu * x5 x3 x4 x2 x1 se te ve se xe brodu * x3 x5 x4 x2 x1 te ve se xe brodu * x4 x3 x5 x2 x1 ve se te xe brodu * x3 x4 x5 x2 x1 se ve se te xe brodu * x5 x4 x2 x3 x1 se ve te se xe brodu * x4 x5 x2 x3 x1 ve te se xe brodu * x5 x2 x4 x3 x1 te ve te xe brodu * x2 x5 x4 x3 x1 se te ve te xe brodu * x4 x2 x5 x3 x1 ve te xe brodu * x2 x4 x5 x3 x1 se ve te xe brodu * x5 x3 x2 x4 x1 se te se xe brodu * x3 x5 x2 x4 x1 te se xe brodu * x5 x2 x3 x4 x1 xe brodu * x2 x5 x3 x4 x1 se xe brodu * x3 x2 x5 x4 x1 te xe brodu * x2 x3 x5 x4 x1 se te xe brodu * x4 x3 x2 x5 x1 se te se ve xe brodu * x3 x4 x2 x5 x1 te se ve xe brodu * x4 x2 x3 x5 x1 ve xe brodu * x2 x4 x3 x5 x1 se ve xe brodu * x3 x2 x4 x5 x1 te ve xe brodu * x2 x3 x4 x5 x1 se te ve xe brodu * x5 x4 x3 x1 x2 xe se ve brodu * x4 x5 x3 x1 x2 se xe se ve brodu * x5 x3 x4 x1 x2 xe se te ve brodu * x3 x5 x4 x1 x2 se xe se te ve brodu * x4 x3 x5 x1 x2 se te xe se ve brodu * x3 x4 x5 x1 x2 te xe se ve brodu * x5 x4 x1 x3 x2 xe se ve te brodu * x4 x5 x1 x3 x2 se xe se ve te brodu * x5 x1 x4 x3 x2 te ve te xe se brodu * x1 x5 x4 x3 x2 se te ve te xe se brodu * x4 x1 x5 x3 x2 ve te xe se brodu * x1 x4 x5 x3 x2 se ve te xe se brodu * x5 x3 x1 x4 x2 xe se te brodu * x3 x5 x1 x4 x2 se xe se te brodu * x5 x1 x3 x4 x2 xe se brodu * x1 x5 x3 x4 x2 se xe se brodu * x3 x1 x5 x4 x2 te xe se brodu * x1 x3 x5 x4 x2 se te xe se brodu * x4 x3 x1 x5 x2 ve xe se te brodu * x3 x4 x1 x5 x2 se ve xe se te brodu * x4 x1 x3 x5 x2 ve xe se brodu * x1 x4 x3 x5 x2 se ve xe se brodu * x3 x1 x4 x5 x2 te ve xe se brodu * x1 x3 x4 x5 x2 se te ve xe se brodu * x5 x4 x2 x1 x3 xe te se ve brodu * x4 x5 x2 x1 x3 se xe te se ve brodu * x5 x2 x4 x1 x3 xe te ve brodu * x2 x5 x4 x1 x3 se xe te ve brodu * x4 x2 x5 x1 x3 te xe te ve brodu * x2 x4 x5 x1 x3 se te xe te ve brodu * x5 x4 x1 x2 x3 se ve se xe te brodu * x4 x5 x1 x2 x3 ve se xe te brodu * x5 x1 x4 x2 x3 xe te ve se brodu * x1 x5 x4 x2 x3 se xe te ve se brodu * x4 x1 x5 x2 x3 te xe te ve se brodu * x1 x4 x5 x2 x3 se te xe te ve se brodu * x5 x2 x1 x4 x3 xe te brodu * x2 x5 x1 x4 x3 se xe te brodu * x5 x1 x2 x4 x3 xe te se brodu * x1 x5 x2 x4 x3 se xe te se brodu * x2 x1 x5 x4 x3 se te xe te brodu * x1 x2 x5 x4 x3 te xe te brodu * x4 x2 x1 x5 x3 ve xe te brodu * x2 x4 x1 x5 x3 se ve xe te brodu * x4 x1 x2 x5 x3 ve xe te se brodu * x1 x4 x2 x5 x3 se ve xe te se brodu * x2 x1 x4 x5 x3 se te ve xe te brodu * x1 x2 x4 x5 x3 te ve xe te brodu * x5 x3 x2 x1 x4 se te se xe ve brodu * x3 x5 x2 x1 x4 te se xe ve brodu * x5 x2 x3 x1 x4 xe ve brodu * x2 x5 x3 x1 x4 se xe ve brodu * x3 x2 x5 x1 x4 te xe ve brodu * x2 x3 x5 x1 x4 se te xe ve brodu * x5 x3 x1 x2 x4 xe ve se te brodu * x3 x5 x1 x2 x4 se xe ve se te brodu * x5 x1 x3 x2 x4 xe ve se brodu * x1 x5 x3 x2 x4 se xe ve se brodu * x3 x1 x5 x2 x4 te xe ve se brodu * x1 x3 x5 x2 x4 se te xe ve se brodu * x5 x2 x1 x3 x4 xe ve te brodu * x2 x5 x1 x3 x4 se xe ve te brodu * x5 x1 x2 x3 x4 xe ve te se brodu * x1 x5 x2 x3 x4 se xe ve te se brodu * x2 x1 x5 x3 x4 se te xe ve te brodu * x1 x2 x5 x3 x4 te xe ve te brodu * x3 x2 x1 x5 x4 te ve xe ve brodu * x2 x3 x1 x5 x4 se te ve xe ve brodu * x3 x1 x2 x5 x4 te se ve xe ve brodu * x1 x3 x2 x5 x4 se te se ve xe ve brodu * x2 x1 x3 x5 x4 se ve xe ve brodu * x1 x2 x3 x5 x4 ve xe ve brodu * x4 x3 x2 x1 x5 se te se ve brodu * x3 x4 x2 x1 x5 te se ve brodu * x4 x2 x3 x1 x5 ve brodu * x2 x4 x3 x1 x5 se ve brodu * x3 x2 x4 x1 x5 te ve brodu * x2 x3 x4 x1 x5 se te ve brodu * x4 x3 x1 x2 x5 ve se te brodu * x3 x4 x1 x2 x5 se ve se te brodu * x4 x1 x3 x2 x5 ve se brodu * x1 x4 x3 x2 x5 se ve se brodu * x3 x1 x4 x2 x5 te ve se brodu * x1 x3 x4 x2 x5 se te ve se brodu * x4 x2 x1 x3 x5 ve te brodu * x2 x4 x1 x3 x5 se ve te brodu * x4 x1 x2 x3 x5 ve te se brodu * x1 x4 x2 x3 x5 se ve te se brodu * x2 x1 x4 x3 x5 se te ve te brodu * x1 x2 x4 x3 x5 te ve te brodu * x3 x2 x1 x4 x5 te brodu * x2 x3 x1 x4 x5 se te brodu * x3 x1 x2 x4 x5 te se brodu * x1 x3 x2 x4 x5 se te se brodu * x2 x1 x3 x4 x5 se brodu * x1 x2 x3 x4 x5 brodu !!!Final note I believe I got all possible conversions in here, but if you see one that's missing, or believe you've found a shorter conversion for a given place structure, then feel free to leave comments. !!!Random musings The largest number of SE cmavo '''required''' for varying number of places is as follows: * 1 place -- no cmavo (only one order possible) * 2 places -- 1 cmavo (only one conversion possible with two places: ''se brode'') * 3 places -- 3 cmavo (only one conversion requires three: ''se te se brodi'') * 4 places -- 4 cmavo (e.g. ''se te se ve brodo'' for order x4 x3 x2 x1) * 5 places -- 6 cmavo (e.g. ''se te ve te xe se brodu'' for order x1 x5 x4 x3 x2) Is there a formula for computing the "maximum minimum" number of SE cmavo for conversions among a given number of place structures? For example, what is the smallest number of SE cmavo required for the re-arrangement of 7 places for the case requiring the largest number of SE cmavo? (Counting "sexida" as one SE cmavo for such purposes since you'll need subscripted SE cmavo once you get beyond 5.) ''Yes. This is a standard question in algebraic combinatorics, or equivelantly a group theory question. Stated mathematically, the question is, given the group S_n - the symmetric group on $n$ letters, and the generating set A = {(1 2), (1 3), ... (1 n)}, what is the maximal length of the elements of S_n according to the generating set A? Hmm... Now that I think of it, this isn't such a simple question. Let me think about it some more.'' -Avital Also, is there a formula for computing the number of variants of equal shortest lenth possible for a given conversion? For example, ''se te se brodi'' can also be ''te se te brodi'', which is two variants. Some conversions of ''brodu'' have 24 variants! (All of those require all six cmavo. Does the number of variants depend on the number of SE cmavo required for that particular conversion?) ''This question is also related to algebraic combinatorics and group theory, and yet again I do not have an immediate answer'' -Avital

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